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What is the velocity of a 16 kg box that has 498 J of KE?

A) 7.1 m/s
B) 14.2 m/s
C) 21.9 m/s
D) 28.2 m/s

User Jstnchng
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1 Answer

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Final answer:

The velocity of a 16 kg box with 498 J of kinetic energy can be calculated using the formula v = √(2 × KE / m), which yields approximately 7.1 m/s.

Step-by-step explanation:

To find the velocity of a 16 kg box that has 498 J of kinetic energy (KE), you can use the kinetic energy formula:

KE = ½ m v²

Where:

  • KE is the kinetic energy
  • m is the mass of the object
  • v is the velocity of the object

First, solve for velocity (v) by rearranging the kinetic energy formula:

v = √(2 × KE / m)

Then plug in the values for kinetic energy (498 J) and mass (16 kg):

v = √(2 × 498 J / 16 kg) = √(996 / 16) = √(62.25) ≈ 7.1 m/s

User Ludovico
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