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What is the angular momentum of a 3.2- kg uniform cylindrical grinding wheel of radius 25 cm when rotating at 1300 rpm ?how much torque is required to stop it in 6.0 s ?

User Josh Jay
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1 Answer

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Final answer:

The angular momentum of a cylindrical grinding wheel is found using its mass, radius, and angular velocity. The torque required to stop it in a given time frame is determined by the rate of change of angular momentum over the stopping time.

Step-by-step explanation:

The angular momentum (L) of a rotating object can be calculated using the moment of inertia (I) and the angular velocity (ω). For a uniform cylindrical grinding wheel, the moment of inertia is given by I = 1/2 m r^2, where m is the mass of the wheel and r its radius. The angular velocity in radians per second can be found by converting the given rotational speed from rpm to rad/s using the conversion factor π/30 rad/s per rpm.

To find the torque (τ) required to stop the wheel, we use the relationship between torque, angular momentum, and time given by τ = ΔL/Δt. Here, ΔL is the change in angular momentum and Δt is the time in which this change occurs.

User Alwin Lazar
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