Question

What are the first five terms of the following sequence? a1 = 42, an = an – 1 – 7 7, 14, 21, 28, 35 42 comma 7 comma 1 comma one seventh comma one forty ninth 42, 35, 28, 21, 14 42, 49, 56, 63, 70

Answer 1

The first five terms of the sequence defined by starting with 42 and subtracting 7 from each preceding term are 42, 35, 28, 21, and 14.

Step-by-step explanation:

The given sequence is defined by a1 = 42, and each subsequent term is found by subtracting 7 from the previous term, i.e., an = an− 1 − 7. To find the first five terms of this sequence, we start with the first term and apply the rule to find the succeeding terms.

First term (a1): 42

Second term (a2 = a1 − 7): 42 − 7 = 35

Third term (a3 = a2 − 7): 35 − 7 = 28

Fourth term (a4 = a3 − 7): 28 − 7 = 21

Fifth term (a5 = a4 − 7): 21 − 7 = 14

Therefore, the first five terms of the sequence are 42, 35, 28, 21, 14.