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The addition of 5.00 g of a compound to 250 g of naphthalene lowered the freezing point of the solvent by 0.780 k. calculate the molar mass of the compound

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Final answer:

To calculate the molar mass of the solute, we can use the formula: Molality (m) = (ΔTf / Kf) * i. In this case, the freezing point depression is 0.780 K, and the freezing point depression constant of naphthalene is 6.80 K kg/mol. Assuming the compound is a non-electrolyte, the van't Hoff factor can be assumed to be 1. Plugging the values into the formula, the molar mass of the compound is calculated to be 177.93 g/mol.

Step-by-step explanation:

To calculate the molar mass of the solute, we can use the formula:

Molality (m) = (ΔTf / Kf) * i

Where ΔTf is the freezing point depression, Kf is the freezing point depression constant of the solvent, and i is the van't Hoff factor.

In this case, the freezing point depression is 0.780 K, and the freezing point depression constant of naphthalene is 6.80 K kg/mol. Assuming the compound is a non-electrolyte, the van't Hoff factor can be assumed to be 1.

Plugging the values into the formula:

m = (0.780 K / 6.80 K kg/mol) * 1 = 0.1147 mol/kg

The molality equation can be rearranged to solve for the moles of solute:

Moles of solute = m * mass of solvent

Mass of solvent = 250 g - 5.00 g = 245 g

Moles of solute = 0.1147 mol/kg * 0.245 kg = 0.0281 mol

Finally, to calculate the molar mass, divide the mass of the solute by the moles:

Molar mass = mass of solute / moles of solute = 5.00 g / 0.0281 mol = 177.93 g/mol

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