Final answer:
The volume of chlorine trifluoride gas produced from a reaction of 3 liters of chlorine gas and 3 liters of fluorine gas, based on the stoichiometry of the reaction and the limiting reagent, is 2 liters.
Step-by-step explanation:
The volume of chlorine trifluoride gas that can be produced from a combination reaction of 3 liters of chlorine gas and 3 liters of fluorine gas can be determined using stoichiometry and the assumption that gases behave ideally. The balanced chemical equation for the reaction is:
Cl
2
(g) + 3F
2
(g) → 2ClF
3
(g)
According to the stoichiometry of the reaction, 1 volume of chlorine gas reacts with 3 volumes of fluorine gas to produce 2 volumes of chlorine trifluoride gas. Therefore, the limiting reagent will determine the maximum volume of ClF3 that can be produced. Since both chlorine and fluorine gases are provided in equal volumes of 3 liters, and fluorine is required in a 3 to 1 ratio, fluorine is the limiting reagent. We can produce 2 liters of ClF3 for every 3 liters of F2 used:
- 3 L F2 → 2 L ClF3
- 3 L F2 (from reaction) → 2 L ClF3 (produced)
Thus, the volume of chlorine trifluoride gas that can be produced from the reaction of 3 liters of chlorine gas with 3 liters of fluorine gas is 2 liters.