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Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kj/g. how many grams of fat will you gain if you eat 10,000 kj (about 2390 kcal) one day and do nothing but sit relaxed for 15.6 h and sleep for the other 8.40 h? (assume energy consumption while sitting relaxed is 120 w and while sleeping is 83 w.)

User Dodi
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Final answer:

The student would gain approximately 17.9 grams of body fat from an excess energy intake of 697.6 kJ, considering a day of minimal activity involving 16 hours of sitting and 8 hours of sleep.

Step-by-step explanation:

The student's question pertains to the conversion of excessive energy intake into body fat as a result of a lack of physical activity to burn off the consumed calories.

To calculate the body fat gain, we first need to determine the total energy expenditure for the day. Here, the person sits relaxed for 16 hours and sleeps for 8 hours. With the energy consumption rates given for these activities (120 W for sitting relaxed and 83 W for sleeping), we can find out how much energy is used in a day.

Energy consumed while sitting relaxed for 16 hours: 120 W * 16 h * 3600 s/h = 6,912,000 J (or 6912 kJ).

Energy consumed while sleeping for 8 hours: 83 W * 8 h * 3600 s/h = 2,390,400 J (or 2390.4 kJ).

Total energy expended: 6912 kJ + 2390.4 kJ = 9302.4 kJ.

If 10,000 kJ is consumed and only 9302.4 kJ is used, the excess energy is 10,000 kJ - 9302.4 kJ = 697.6 kJ.

The amount of fat gained from this excess energy: 697.6 kJ / 39 kJ/g = 17.9 grams of fat.

User Cesar Daniel
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