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Write an equation of the parabola in intercept form that passes through (-2, 27) with x-intercepts of 7 and 10

User RodXander
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Final answer:

To write an equation of a parabola in intercept form, we can start by using the x-intercepts. Using the point (-2, 27), we can substitute its coordinates into the equation to find the value of 'a'. Once 'a' is found, we can write the equation of the parabola in intercept form.

Step-by-step explanation:

To write an equation of a parabola in intercept form, we can start by using the x-intercepts. The general form of the equation is given by y = a(x-x1)(x-x2), where (x1, 0) and (x2, 0) are the x-intercepts. Given x-intercepts of 7 and 10, the equation becomes y = a(x-7)(x-10).

Using the point (-2, 27), we can substitute its coordinates into the equation to find the value of 'a'. Plugging in the values, we get 27 = a(-2-7)(-2-10). Solving this equation will give us the value of 'a'. Once 'a' is found, we can write the equation of the parabola in intercept form.

User Xaphann
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