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A bicyclists speeds up from rest to 9.00m/s during a 5.10s time interval.

User Activars
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Final answer:

The cyclist's final velocity after accelerating at 0.500 m/s² for 7.00 s from an initial velocity of 11.5 m/s is 15.0 m/s.

Step-by-step explanation:

The question asks about determining the final velocity of a cyclist who accelerates at a known rate for a certain period. To calculate this, we use the formula for final velocity in uniform acceleration: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. The cyclist begins with an initial velocity of 11.5 m/s and accelerates at 0.500 m/s² for 7.00 s.

Using the formula, the final velocity is calculated as:

v = u + at
v = 11.5 m/s + (0.500 m/s² × 7.00 s)
v = 11.5 m/s + 3.5 m/s
v = 15.0 m/s

So the cyclist's final velocity is 15.0 m/s.

User Adriang
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