129k views
2 votes
A sled of mass four KG is celebrated uniformly infection this I surface at the rate of 2.5 m/s square for 10 seconds determine the network done on the side

User Carole
by
7.3k points

1 Answer

3 votes

The work done on the sled, accelerated uniformly at 2.5 m/s^2 for 10 seconds, is 1250 Joules.

To determine the work done on the sled, we can use the formula for work done, which is given by:

Work = Force × Distance

In this case, the force can be calculated using Newton's second law:

Force = Mass × Acceleration

The sled's mass is given as 4 kg, and the acceleration is provided as 2.5 m/s^2. Using these values, we find the force acting on the sled.

Force = 4 kg × 2.5 m/s^2 = 10 N

Now, to find the distance traveled, we can use the kinematic equation:

Distance = Initial Velocity × Time + 1/2 × Acceleration × Time^2

The initial velocity is not given, so assuming it's 0 m/s (starting from rest), we can simplify the equation to:

Distance = 1/2 × Acceleration × Time^2

Plugging in the values (Acceleration = 2.5 m/s^2, Time = 10 s), we find the distance traveled.

Distance = 1/2 × 2.5 m/s^2 × (10 s)^2 = 125 m

Now, substitute these values into the work formula:

Work = Force × Distance = 10 N × 125 m = 1250 J

Therefore, the work done on the sled is 1250 Joules.

User Valath
by
7.5k points