Question

Admission to a baseball game is $3.50 for general admission and $5.50 for reserved seats. The receipts were $3907.50 for 965 paid admissions. How many of each ticket were sold?

Answer 1

700 general admission tickets and 265 reserved seat tickets were sold.

Explanation:

Let’s denote the number of general admission tickets sold as x and the number of reserved seat tickets sold as y.

From the problem, we have two equations:

The total number of tickets sold is 965, so x + y = 965.

The total revenue from the tickets is $3907.50. Given that general admission tickets cost $3.50 and reserved seat tickets cost $5.50, we can write this as 3.5x + 5.5y = 3907.5.

We can solve this system of equations to find the values of x and y. Let’s do it.

First, multiply the first equation by 3.5 to make the coefficients of x in both equations the same:

3.5x + 3.5y = 3377.5

Now, subtract this new equation from the second equation:

2y = 530

Dividing both sides by 2 gives y = 265.

Substituting y = 265 into the first equation gives x = 965 - 265 = 700.

So, 700 general admission tickets and 265 reserved seat tickets were sold.

Answer 2

1,116 were sold for $3.50.

710 tickets were sold for 5.50.

Explanation:

All I did was divide the total receipt cost by each ticket price for the answer.

Ex: $3097.50 Divided by $5.50 = 710.

I hope this helps.