Final answer:
To derive the molarity equation from a balanced chemical equation, you must understand the stoichiometric ratios involved. Calculate the moles of solute and divide by the solution's volume in liters. The molarity (M) equals the moles of solute (n) divided by the volume of solution (V).
Step-by-step explanation:
Deriving the Equation for Calculation of Molarity
To derive the equation for the calculation of molarity based on a balanced chemical equation, you first need to understand the stoichiometry of the reaction. The question indicates an incorrect reaction equation. However, to provide an example with a correct equation, let's consider the reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH):
H2SO4 (aq) + 2NaOH(aq) → Na2SO4 (aq) + 2H2O(l)
The balanced chemical equation indicates that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. To find the molarity of the NaOH solution, calculate the moles of solute present in a known volume of solution. Use the formula:
M = n/V
Where M represents molarity, n is the number of moles of the solute (NaOH), and V is the volume of the solution in liters. The balanced equation provides the stoichiometric ratio needed to relate the moles of sulfuric acid and sodium hydroxide. For example, if you know the molarity and volume of H2SO4 that reacted, you can use the mole ratio to find the moles of NaOH. Then, divide this number by the volume of the NaOH solution in liters to calculate its molarity.