Question

Given the following nuclear reaction: 223 87 3. Fre-4X Column A 1. k What is the atomic mass of the new atom? 2. b What is the atomic number of the new atom? What is the symbol of the new atom? What type of decay is demonstrated here? TINGINE f m Column B a. 86 b. 87 c. Alpha Decay d. 222 e. Ac f. Fr g. 88 h. Ra i. 89 j. 224 k. 223 1. Gamma Decay m. Beta Decay​

Answer 1

1. The atomic mass of the new atom is 223.
2. The atomic number of the new atom is 88.
3. The symbol of the new atom is Ra.
4. The type of decay demonstrated here is Beta Decay.

The given nuclear reaction is:

`$$^(223)_(87)\text{Fr} \rightarrow ^0_(-1)\text{e} + ^4_Z\text{X}$$`

This is a beta decay process, where a neutron in the nucleus of the Francium (Fr) atom converts into a proton, releasing an electron (also known as a beta particle) in the process.

The atomic mass and atomic number of the new atom (X) can be determined by balancing the atomic masses and atomic numbers on both sides of the equation.

Balancing the atomic masses gives:

`223 = 0 + A`

So, the atomic mass (A) of the new atom is 223.

Balancing the atomic numbers gives:

`$$87 = -1 + Z$$`

So, the atomic number (Z) of the new atom is 88.

The new atom with atomic number 88 is Radium (Ra).

In summary, the answers to the questions in the image are:

• The atomic mass of the new atom is 223.
• The atomic number of the new atom is 88.
• The symbol of the new atom is Ra.
• The type of decay demonstrated here is Beta Decay.