Question

What’s the answer to this problem

Answer 1

The concentration of the
`[H_2SO_4]` solution in the image is 0.1481 M.

Balanced chemical equation for the titration reaction:

2 NaOH +
`[H_2SO_4]` →
`Na_2SO_4 + 2 H_2O`

According to the equation, 2 moles of NaOH react with 1 mole of
`H_2SO_4`. Therefore, the concentration of the
`[H_2SO_4]` solution can be calculated using the following equation:

`[H_2SO_4]` = (Molarity of NaOH solution) * (Volume of NaOH solution used) / (Volume of
`H_2SO_4` solution used)

In this case, the molarity of the NaOH solution is 0.1217 M and the volume of NaOH solution used is 30.57 mL. The volume of H2SO4 solution used is 25.00 mL.

Substituting these values into the equation above, we get:

`[H_2SO_4]` = (0.1217 M) * (30.57 mL) / (25.00 mL)

`[H_2SO_4]` = 0.1481 M

Question:-

25.00 ml. of a H₂SO₄ solution with an unknown concentration was titrated to a phenolphthalein endpoint with 30.57 m² of a 0.1217 M NaOH solution.

What is the concentration of the H₂SO₄ solution?