Question

The bottom of the Mariana Trench is about 11 km below the surface of the ocean. Calculate the pressure at this depth if the density of sea water is ρ = 1025kg/m 3. How many atmosphere’s worth of pressure is this?

Answer 1

p=1107.1

Step-by-step explanation:

formula: [ P = \rho g h ]

depth(h)=11km

change to m= 11,000 m

h=11,000

density sea water( ρ)= 1025kg/m3

ρxh= 1025x 11,000= 11275000 pa( pascal)

1 atmosphere (atm) is approximately equal to the average atmospheric pressure at sea level, which is 101,325

p=11275000 divided by 101325

p=1107.081174

to convert it to the nearest decimal

p=1107.1