Final answer:
The y-intercepts of the equation x=y^2+3y+2 are (0,-2) and (0,-1).
The x-intercepts are (-2,0) and (-1,0).
Step-by-step explanation:
To find the y-intercept, we set x=0 in the equation and solve for y.
Plugging in x=0, we get y^2+3y+2=0.
Solving this quadratic equation, we find that y=-2 or y=-1.
Therefore, the y-intercepts are (0,-2) and (0,-1).
To find the x-intercepts, we set y=0 in the equation and solve for x.
Plugging in y=0, we get x^2+3x+2=0.
Solving this quadratic equation, we find that x=-2 or x=-1.
Therefore, the x-intercepts are (-2,0) and (-1,0).