Final answer:
To achieve a 95% confidence that the estimate is within 4.25 of the true population mean with a known standard deviation of 70.7, a sample size of 1079 is required.
Step-by-step explanation:
To calculate the required sample size to estimate a population mean with a specified margin of error and confidence level, we use the formula for the sample size of a mean:
n = (Z*σ/E)2
Where:
- n is the sample size
- Z is the Z-score corresponding to the desired confidence level
- σ is the population standard deviation
- E is the margin of error
For a 95% confidence level, the Z-score is approximately 1.96. Given that σ is 70.7 and the desired margin of error E is 4.25, we can plug these values into the formula:
n = (1.96*70.7/4.25)2 = (139.572/4.25)2 = 32.840242 = 1078.202
Since we cannot have a fraction of a person in the sample size, we round up to the nearest whole number:
n = 1079