Final answer:
The first equation suggests games and rides cost the same, which is incorrect. The second equation implies games could cost $2 each, which they don't. The last equation aligns with the given costs, representing $1 games and $2 rides accurately.
Step-by-step explanation:
The question given by Jada shows three different linear equations, each representing the total cost of $20 that she has to spend on games and rides at a carnival. Let's say that x represents the number of games and y represents the number of rides. The first equation, x + y = 20, suggests that games and rides each cost the same amount. This seems incorrect since the problem statement specifies that games cost $1 each and rides cost $2 each. The second equation, 2x + y = 20, indicates double the number of games plus the number of rides equals 20, allowing us to delve into a scenario where games could potentially cost $2 each, which they do not. Finally, the third equation, x + 2y = 20, describes a situation where the cost of the games plus twice the cost of rides equals 20; this correctly aligns with the given costs of games and rides.