Final answer:
To calculate the distance of the vertical jump, the height achieved during the half-time of the motion (0.36s/2) was determined using the physics equation for uniformly accelerated motion, and then the height was doubled to obtain the total distance jumped, which is approximately 1.27 meters.
Step-by-step explanation:
The student's question pertains to the distance one can jump vertically into the air and land 0.36 seconds later. To solve for the vertical distance traveled, we can use the physics equations of uniformly accelerated motion. The time in the air is t = 0.36 s. Assuming the acceleration due to gravity (g) is 9.81 m/s² and that vertical velocity is zero at the jump's peak, we can use the equation h = 0.5 × g × t² to find the height.
Substituting the values gives us: h = 0.5 × 9.81 m/s² × (0.36 s)² = 0.635 m. However, because the object is going up and then coming down to the same level - this distance will be covered twice - once going up and once coming down. So the total distance jumped is 2 × 0.635 m = 1.27 m. Therefore, the student jumped approximately 1.27 meters.