88.9k views
1 vote
equation of a parabola in vertex form that has been compressed vertically by a factor of 1/5 and shifted down 6

User MKaama
by
8.7k points

1 Answer

3 votes

Final answer:

The equation of a parabola that has been vertically compressed by a factor of 1/5 and shifted down 6 units in vertex form is y = (1/5)(x - h)^2 - 6, where (h, k) is the vertex and h is the x-coordinate of the vertex.

Step-by-step explanation:

The vertex form of a parabola is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola. If a parabola is compressed vertically by a factor of 1/5, the coefficient a would be 1/5. Also, if it is shifted down by 6 units, the k in the vertex form would be -6. Therefore, the desired equation of the parabola in vertex form would be y = (1/5)(x - h)^2 - 6, where h is the x-coordinate of the vertex, which is not given in the problem, and thus remains as the variable h.

User Josiah Ruddell
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.