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Use the intercepts to graph the equation -5x + 10y = 30?

User Ragunathan
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X-intercept: (-6, 0); Y-intercept: (0, 3). Connect to plot the line representing -5x + 10y = 30.

To graph the equation -5x + 10y = 30, let's find its intercepts: the x-intercept and the y-intercept.

1. X-intercept (when y = 0):

To find the x-intercept, substitute y = 0 into the equation and solve for x.

-5x + 10y = 30

-5x + 10(0) = 30

-5x = 30

x =
(30)/(-5)

x = -6\)

The x-intercept is (-6, 0).

2. Y-intercept (when x = 0):

To find the y-intercept, substitute x = 0 into the equation and solve for y.

-5x + 10y = 30

-5(0) + 10y = 30

10y = 30


\(y = (30)/(10)\)

y = 3

The y-intercept is (0, 3).

Now, let's plot these intercepts on the coordinate plane.

The x-intercept (-6, 0) is located at -6 on the x-axis.

The y-intercept (0, 3) is located at 3 on the y-axis.

Once both intercepts are plotted, draw a straight line passing through these two points. This line represents the graph of the equation -5x + 10y = 30. Since the x-intercept is at -6 and the y-intercept is at 3, connect these points to form a straight line. This line represents all the points that satisfy the equation.

Use the intercepts to graph the equation -5x + 10y = 30?-example-1
User Nazariy
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