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A 5-kg mass attached to the end of a string is spun in a vertical circle of radius 1.5-meters, with a constant velocity of 3-m/s. What is the tension in the string at at its lowest point?

User Zhuyxn
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Final answer:

The tension in the string at the lowest point is 30 N.

Step-by-step explanation:

To find the tension in the string at the lowest point of the vertical circle, we need to consider the forces acting on the 5-kg mass. At the lowest point, the tension in the string provides the centripetal force, which is given by the equation T = mv^2/r, where T is the tension, m is the mass, v is the velocity, and r is the radius. In this case, m = 5 kg, v = 3 m/s, and r = 1.5 m. Plugging in these values, we get T = (5 kg)(3 m/s)^2 / 1.5 m = 30 N.

User Primehalo
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