Answer:
see explanation
Explanation:
(a)
The angle around the centre O of the circle = 360°, then
∠ AOB = 360° - 260° = 100°
Δ AOB is isosceles ( the radii OA and OB are congruent )
The altitude from O bisects ∠ AOB , thus
y = 50°
Since the triangle is isosceles the 2 base angles are congruent, so
x =
=
= 40°
(b)
∠ POR = 360° - 254° = 106°
Δ POR is isosceles (the radii OP and OR are congruent ) , then
the 2 base angles are congruent , thus
a =
=
= 37°