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(x − 2)² − 3 in standard form
y = -(x+3)² + 3 Graph
y = x² - 6x + 5 Graph

User Evelynn
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1 Answer

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The given equation (x - 2)² - 3 is in standard form x² - 4x - 2. To graph y = -(x+3)² + 3, find the vertex (-3, 3) and plot points on either side. For y = x² - 6x + 5, the vertex is (3, -4) and the parabola opens upward.

Step-by-step explanation:

The given equation (x − 2)² − 3 can be expanded and simplified to x² - 4x + 1. To put it in standard form, we arrange the terms in descending order of the degree of x. So the standard form of the equation is x² - 4x + 1 - 3 = x² - 4x - 2.

To graph the equation y = -(x+3)² + 3, we start by finding the vertex, which is (-3, 3) because the equation is in the vertex form y = a(x-h)² + k. The negative value of a indicates a downward opening parabola. We can plot points on either side of the vertex and draw a smooth curve passing through these points.

To graph the equation y = x² - 6x + 5, we first rewrite it as y = (x - 3)² - 4. The vertex is (3, -4) and the parabola opens upward. By plotting points on either side of the vertex, we can draw the graph.

(x − 2)² − 3 in standard form y = -(x+3)² + 3 Graph y = x² - 6x + 5 Graph-example-1
(x − 2)² − 3 in standard form y = -(x+3)² + 3 Graph y = x² - 6x + 5 Graph-example-2
User Oktalist
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