Final answer:
The concentration of chromate ions in a 0.0388 mol/L solution of Al2(CrO4)3 is 0.116 mol/L.
Step-by-step explanation:
The concentration of chromate ions in a 0.0388 mol/L solution of Al2(CrO4)3 is 0.116 mol/L.
To determine this, we need to use the stoichiometry of the compound. Al2(CrO4)3 dissociates into 3 CrO42- ions per formula unit. So, the concentration of chromate ions is 3 times the concentration of Al2(CrO4)3.
Therefore, the concentration of chromate ions is 3 × 0.0388 mol/L = 0.116 mol/L.