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Solve (x⁶-2x⁵+x⁴-x³+3x²-x+24)/x+2 using long division.

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Final answer:

To solve the expression (x⁶-2x⁵+x⁴-x³+3x²-x+24)/(x+2) using long division, divide the terms of the numerator by the denominator, and subtract the results from the numerator until the remainder is smaller than the denominator.

Step-by-step explanation:

To solve the expression using long division:

  • Divide the first term of the numerator by the denominator.
  • Multiply the quotient by the denominator, and subtract it from the numerator.
  • Repeat the process until the numerator is smaller than the denominator.
  • The final quotient is the answer.

In this case, the expression is (x⁶-2x⁵+x⁴-x³+3x²-x+24)/(x+2).

Following the steps of long division, we have:

x⁵-3x³+7x²-13x+26

_____________

x+2 ∣ x⁶-2x⁵+x⁴-x³+3x²-x+24

-x⁶-2x⁵

_____________

0x⁵+x⁴-x³+3x²

0x⁵+2x⁴

_____________

-2x⁴-x³+3x²-x

-2x⁴-4x³

_____________

3x³+3x²-x

3x³+6x²

_____________

-9x²-x

-9x²-18x

_____________

17x+24

17x+34

_____________

-10

So, the solution to the expression (x⁶-2x⁵+x⁴-x³+3x²-x+24)/(x+2) using long division is x⁵-3x³+7x²-13x+26 with a remainder of -10.

User Bernard Potocki
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