201k views
3 votes
Given the following equation: 2 K + Cl → 2 KCl. How many grams of KCl is produced from 9.50 g of K and excess CI.

A. 12.4 g KCI
B. 14.2 g KCI
C. 18.1 g KCI
D. 24.8 g KCI

User Adzz
by
7.8k points

1 Answer

3 votes

Final answer:

To find the mass of KCl produced from 9.50 g of K, we can use stoichiometry and molar mass calculations.

Step-by-step explanation:

To find the mass of KCl produced, we need to use the concept of stoichiometry. From the balanced equation, we can see that 2 moles of KCl are produced for every 2 moles of K. This means that the mole ratio of K to KCl is 1:1. We can use the molar mass of KCl (74.55 g/mol) to convert the moles of K to grams of KCl.

Given that we have 9.50 g of K, we can calculate:

(9.50 g K) x (1 mol K/39.10 g K) x (74.55 g KCl/1 mol KCl) = 18.1 g KCl

Therefore, the correct answer is 18.1 g KCl.

User CaffGeek
by
8.0k points