Question

David is buying hot dogs and buns for a picnic. hot dogs are sold in packs of 8, and buns come in packs of 6. what is the least amount of packs of hotdogs and buns david can buy so he has an equal amount of both?

Answer 1

David needs to buy 24 hot dogs (3 packs of 8) and 24 buns (4 packs of 6) to have an equal amount of both.

Step-by-step explanation:

To find the least amount of packs of hotdogs and buns David can buy so he has an equal amount of both, we need to find the least common multiple (LCM) of 8 and 6. The LCM is the smallest number that both 8 and 6 can divide into evenly.

The prime factors of 8 are 2 x 2 x 2, and the prime factors of 6 are 2 x 3. To find the LCM, we take the highest power of each prime factor between the two numbers: 2 x 2 x 2 x 3 = 24.

Therefore, David needs to buy 24 hot dogs (3 packs of 8) and 24 buns (4 packs of 6) to have an equal amount of both.

Answer 2

David would need to buy 3 packs of hot dogs (8 hot dogs each) and 4 packs of buns (6 buns each) to have an equal amount of both.

Step-by-step explanation:

To find the least amount of packs of hotdogs and buns that David can buy so he has an equal amount of both, we need to find the least common multiple (LCM) of 8 and 6. The LCM is the smallest number that both 8 and 6 divide into evenly.

The prime factorization of 8 is 2 x 2 x 2, and the prime factorization of 6 is 2 x 3. To find the LCM, we need to take the highest power of each prime factor that appears in either number. So the LCM of 8 and 6 is 2 x 2 x 2 x 3 = 24.

Therefore, David would need to buy 3 packs of hot dogs (8 hot dogs each) and 4 packs of buns (6 buns each) to have an equal amount of both.