Final answer:
To find the mass of the solute glucose in 0.470 L of a 0.59 M solution, calculate the number of moles from the molarity and volume, then multiply by the molar mass of glucose to get 49.99 g.
Step-by-step explanation:
To determine the mass of the solute (glucose) in a given solution, we can use the formula:
mass of solute = molarity (M) × volume of solution (L) × molar mass of solute (g/mol).
In this case, the molarity of the glucose solution is 0.59 M, the volume of the solution is 0.470 L, and the molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.
First, we calculate the number of moles of glucose using molarity and volume:
0.59 moles/L × 0.470 L = 0.2773 moles of glucose
Then, we find the mass by multiplying the number of moles by the molar mass:
0.2773 moles × 180.16 g/mol = 49.99 g (rounded to two decimal places)
Therefore, the mass of the solute glucose in 0.470 L of a 0.59 M solution is 49.99 g.