Question

A student is provided with a specimen of tilapia of length 10cm. The student made a drawing of the specimen of length 12cm. Calculate the Magnification of the drawing.​

Answer 1

1.2 is the magnification of the drawing

Step-by-step explanation:

According to the question,

Actual length of tilapia specimen provided to a student = 10 cm

Drawing length made by student of the specimen= 12 cm

`\rm Magnification \: of \: the \: drawing= (Actual \: length \: of \: the \: specimen)/(Drawing \: length \: of \: the \: specimen) \\ \\ \rm= (12)/(10) \\ \\ \rm = 1.2`