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A 1500 g block is hung from a vertical spring, causing the spring to stretch by 30 mm. How much farther will the spring stretch if an 800 kg block is added to the 1500 g block?

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The spring will stretch an additional 157.57 meters when the 800 kg block is added.

Here's how to calculate the additional stretch of the spring:

Step 1: Convert masses to kilograms.

1500 g = 1.5 kg

800 kg (already in kilograms)

Step 2: Calculate the total mass.

Total mass = 1.5 kg + 800 kg = 801.5 kg

Step 3: Calculate the spring constant.

We're given that the spring stretches by 30 mm (0.03 m) for a mass of 1.5 kg.

Using Hooke's Law: F = kx, where F is the force, k is the spring constant, and x is the displacement.

In this case, the force is the weight of the block: F = mg (m is the mass, g is the acceleration due to gravity, 9.81 m/s²).

Therefore, mg = kx.

Substituting known values: (1.5 kg)(9.81 m/s²) = k(0.03 m).

Solving for k: k ≈ 490.5 N/m.

Step 4: Calculate the stretch due to the total mass.

Using the same formula as before: F = kx.

This time, F = (801.5 kg)(9.81 m/s²) and k = 490.5 N/m.

Solving for x: x ≈ 157.6 m.

Step 5: Calculate the additional stretch.

Additional stretch = Total stretch - Initial stretch

Additional stretch = 157.6 m - 0.03 m

Additional stretch ≈ 157.57 m

Therefore, the spring will stretch an additional 157.57 meters when the 800 kg block is added.

User Robinr
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