Question

A motorcyclist heading east accelerates after he passes a sign post at x=0m marking the city his acceleration is constant a= 4m/s2 at time=0 he is 5m east of the sign post and has a velocity of v=15 m/s where is the motorcyclist when his velocity is 25m/s

Answer 1

55m east of the sign post

Step-by-step explanation:

Use this equation

final velocity^2 = initial velocity^2+2(a)(x) x is displacement.

Substitute values:

25^2= 15^2+ 2(4)(x)

625=225+8x

x=50 m

REMEMBER TO ADD INITIAL DISPLACEMENT!!!! :D

Displacement (positive is east in this case)

=50 m+ 5m

=55m.

So the answer is the motorcyclist is 55m east of the sign post.