Final answer:
The upper limit of the median class for the given frequency distribution is the value that marks the end of the class interval containing the median. By calculating the cumulative frequencies, we find that the third interval (12-17) is the median class, with the upper limit being 17.
Step-by-step explanation:
The question is asking to find the upper limit of the median class from a given frequency distribution. To find the median class, we must first determine the cumulative frequency of each class and then find the class interval that contains the median. The median is the value that divides the dataset into two equal halves, so we need to find half the total frequency.
In this case, the cumulative frequency up to the first class interval is 26, up to the second is 46 (26+20), up to the third is 76 (46+30), up to the fourth is 92 (76+16), and up to the fifth is 114 (92+22). The total frequency is 114, so half of this is 57. The median class is the class interval where the cumulative frequency reaches or surpasses 57. The third interval (12-17) is the median class as its cumulative frequency is 76, which encompasses the 57th value.
The upper boundary of the third class interval (12-17) is the answer we are looking for. Therefore, the upper boundary, or upper limit of the median class, is 17. The correct option is (d) 17.