Final answer:
After substituting x with 15 in each equation, we find that x = 15 is a solution to equations A, B, and D.
Step-by-step explanation:
To determine which equations have x = 15 as a solution, we need to substitute x with 15 in each equation and check if it's true.
- For equation A (3x = 45), substituting x with 15 gives us 3(15) = 45, which simplifies to 45 = 45. This is true, so x = 15 is a solution to equation A.
- For equation B (x/10 = 1.5), substituting x with 15 gives us 15/10 = 1.5, which simplifies to 1.5 = 1.5. This is true, so x = 15 is a solution to equation B.
- For equation C (x - 12 = 27), substituting x with 15 gives us 15 - 12 = 27, which simplifies to 3 = 27. This is false, so x = 15 is not a solution to equation C.
- For equation D (x + 4 = 19), substituting x with 15 gives us 15 + 4 = 19, which simplifies to 19 = 19. This is true, so x = 15 is a solution to equation D.
- For equation E (2x = 10), substituting x with 15 gives us 2(15) = 10, which simplifies to 30 = 10. This is false, so x = 15 is not a solution to equation E.
Therefore, x = 15 is a solution to equations A, B, and D.