Question

An irregular shaped object was lowered into a graduated cylinder holding a volume of water equal to 50 mL. The height of the water rose to 70. If the mass of the stone was 140, what was its density? Show all of your work to earn full credit, including units.

Answer 1

To find the density, the mass of the object (140 g) is divided by the volume of water displaced (20 cm³), resulting in a density of 7 g/cm³.

To calculate the density of an irregularly shaped object, we use the formula density (ρ) = mass (m) / volume (V). The mass of the object is given as 140 (units are not specified but are likely grams). To find the volume of the object, we subtract the initial volume of water in the graduated cylinder from the final volume after submersion: 70 mL - 50 mL = 20 mL. Hence, the volume displaced by the object is 20 mL, which is equivalent to 20 cm³, since 1 mL = 1 cm³.

ρ = m / V = 140 g / 20 cm³ Therefore, the density of the object is 7 g/cm³.