h(6)=−15.
To find ℎ(6)
h(6) for the given function
ℎ(x) = −2x −3
h(x)=−2x−3, substitute
x=6 into the function:
h(6)=−2(6)−3
Now, perform the calculations:
h(6)=−12−3=−15
Therefore,
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