31.5k views
4 votes
Edna leaves the trailhead at 7 AM to hike 12 miles towards the lake where Maria is camping. Edna’s progress is tracked on the graph below. At the same time, Maria starts her hike from the lake back to the trailhead. Maria walks at a rate of 1/2 a mile per hour. When and where will they meet? A) At 12 PM, 3 miles from the trailhead B) At 1 PM, 6 miles from the trailhead C) At 1 PM, 9 miles from the trailhead D) At 6 PM, 9 miles from the trailhead

User Mazzaroth
by
8.1k points

1 Answer

5 votes

They will meet at 1 PM, 6 miles from the trailhead and the correct option is C.

Edna leaves the trailhead at 7 AM and needs to hike 12 miles to the lake. Maria hikes at a rate of 1/2 mile per hour, and starts hiking from the lake at the same time as Edna.

We can calculate the time it takes Edna to reach the lake by dividing the distance by Maria's rate:

edna_time_to_lake = edna_distance / maria_rate

edna_time_to_lake = 12 miles / 0.5 miles per hour

edna_time_to_lake = 24 hours

Maria starts hiking at the same time as Edna, so she has been hiking for 24 hours when they meet. We can calculate the distance Maria has traveled by multiplying her rate by the time she has been hiking:

maria_distance_traveled = maria_rate * maria_time_hiking

maria_distance_traveled = 0.5 miles per hour * 24 hours

maria_distance_traveled = 12 miles

Since Maria has traveled 12 miles and Edna has traveled 12 miles, they must meet at the lake.

We can calculate the total time it takes for them to meet by adding the time it takes Edna to reach the lake and the time it takes Maria to reach the trailhead:

total_time = edna_time_to_lake + maria_time_to_trailhead

total_time = 24 hours + 24 hours

total_time = 48 hours

Converting the total time to hours and minutes, we get:

hours, minutes = divmod(total_time, 1)

hours = 48 // 1

minutes = 48 % 1 * 60

hours = 48

minutes = 0

Therefore, they will meet at 48 PM, 0 minutes past the hour, at the lake.

So the answer is At 1 PM, 9 miles from the trailhead and the correct option is C.

User Brennan
by
7.3k points