Question

A rock is kicked horizontally off the edge of a cliff at a velocity of 3.0 meters per second. If the canyon below is 110 meters deep, how far from the edge of the cliff does the rock land

Answer 1

To find the distance the rock lands from the edge of the cliff, use the equation d = v t, where v is the velocity and t is the time. Plug in the given values and solve.

Step-by-step explanation:

To determine the horizontal distance the rock will land from the edge of the cliff, we can use the equation d = v t, where d is the distance, v is the velocity, and t is the time. In this case, the velocity is given as 3.0 meters per second, and the time is calculated by dividing the depth of the canyon (110 meters) by the gravitational acceleration (9.8 m/s²). Plugging these values into the equation, we have:

d = (3.0 m/s) × (110 m / (9.8 m/s²))

Simplifying this equation will give us the distance the rock lands from the edge of the cliff.