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The roots of equation −6x²+24x+12=0 are:

a. real, rational, and equal.
b. imaginary.
c. real, irrational, and unequal.
d. real, rational, and unequal.

User Rojzik
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1 Answer

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Final answer:

The equation −6x²+24x+12=0 has a positive discriminant which is a perfect square, indicating that its roots are real, rational, and since the square root of the discriminant is not an integer, the roots are unequal.

Step-by-step explanation:

To determine if the roots of the equation −6x²+24x+12=0 are real, rational, imaginary, or irrational, we can calculate the discriminant from the quadratic formula. The discriminant is found by the formula b² - 4ac, where a, b, and c are coefficients of the equation ax² + bx + c = 0. In this case, a = -6, b = 24, and c = 12.

Lets calculate the discriminant:

discriminant = b² - 4ac = (24)² - 4(-6)(12) = 576 + 288 = 864

The discriminant is positive, which means the equation has two real roots. Since it is a perfect square (144²), the roots are also rational. Finally, as the discriminant does not yield a perfect square of an integer under the square root, we can deduce that the equation has two real, rational, and unequal roots.

Therefore, the correct answer is: d. real, rational, and unequal.

User NoDachi
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