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The beaker containing 80% water and 20% salt a bag containing 95% water was placed in. What was the change on the bag or content?

User XAoc
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Final answer:

When a bag containing 95% water is placed in a beaker with 80% water, osmosis will occur, with water moving from the bag to the beaker to attempt to equalize solute concentrations, leading to changes in volume and concentration in both the bag and beaker.

Step-by-step explanation:

The question seems to be asking about the effects of immersing a bag containing a specific concentration of water (95% water and 5% solute) into a beaker with a different concentration (80% water and 20% salt). This is a question related to the principles of osmosis, which is the movement of water across a semi-permeable membrane from an area of lower solute concentration to an area of higher solute concentration.

When the bag with 95% water is placed in the beaker containing 80% water, there is a concentration gradient between the contents of the bag and the beaker. Osmosis will cause water to move out of the bag and into the beaker in an attempt to equalize the solute concentrations on both sides of the bag's semi-permeable membrane. Over time, this would lead to an increase in the volume of fluid in the beaker and a decrease in the volume of fluid within the bag, as well as changes in the concentration of solutes within both the bag and the beaker.

It's important to note that this is a simplified description and the actual process can be influenced by various factors such as the type of membrane, the specific solutes present, and the temperature and pressure conditions.

User Bilgin
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