Final answer:
To factor u^3 + 125 completely, it can be expressed as (u + 5)(u^2 - 5u + 25), using the sum of cubes formula.
Step-by-step explanation:
To factor u^3 + 125 completely, we recognize this as a sum of cubes because 125 = 5^3. A sum of cubes can be factored using the formula a^3 + b^3 = (a + b)(a^2 - ab + b^2). Applying this to u^3 + 5^3, we get (u + 5)(u^2 - 5u + 25).
The equation provided for the nuclear reaction, 235U + n → 95Mo + 139La + 2n + energy, illustrates that mass and atomic numbers are conserved in a nuclear reaction. The provided periodic table information, such as 92 U 93 Np 94 Pu 95 Am, is relevant to the chemistry of elements and their electrons configuration but not directly applicable to factoring the given mathematical expression.
The section discussing the normalization constant and the integral of f(v)du is tackling probability density functions, which is a different mathematical concept.