Question

"Bryant and Annissa are getting cookies for their math class. They have a total budget of $75 to spend at the bakery. Chocolate chip cookies cost $1.50 each and sugar cookies cost $0.75 each. They spent $18.75 on sugar cookies. How many chocolate chip cookies, C, can they afford with the rest of their budget?

Let C = the number of chocolate chip cookies. Let S = the number of sugar cookies.
a Write an inequality that relates C and S based on the information in the problem.
b Solve your inequality. What is your solution as an inequality statement? (e.g., x ≤ 3)
c Write a statement analyzing your solution using the context of the situation.

Answer 1

To find the number of chocolate chip cookies they can afford, we can write an inequality based on the budget, cost per cookie, and the number of sugar cookies purchased. The inequality is 1.50C + 0.75(25) ≤ 75. By solving the inequality, we find that they can afford 37 chocolate chip cookies.

Step-by-step explanation:

To write an inequality relating the number of chocolate chip cookies, C, and the number of sugar cookies, S, we need to consider the budget and cost of each type of cookie.

Let's assume that the number of chocolate chip cookies they can afford is represented by C and the number of sugar cookies they purchased is already given as 18.75/0.75 or 25.

The total budget is $75, and the cost of each chocolate chip cookie is $1.50. So, the total cost of the chocolate chip cookies would be 1.50C.

Therefore, the inequality that relates C and S based on the given information is: 1.50C + 0.75(25) ≤ 75

To solve this inequality, we can simplify it:

1. 1.50C + 18.75 ≤ 75 (Substituted the value of S)
2. 1.50C ≤ 75 - 18.75
3. 1.50C ≤ 56.25
4. C ≤ 56.25 ÷ 1.50 or C ≤ 37.5

Therefore, they can afford 37 chocolate chip cookies within their budget.