Final answer:
To make 1500 cm³ of the test solution, you would need approximately 31.27 grams of PbBr⁴.
Step-by-step explanation:
To find the mass of PbBr⁴ needed to make 1500 cm³ of the test solution, we first need to calculate the number of moles of Pb⁴+ ions present in the solution. We know that the concentration of Pb⁴+ ions is 15 mg/cm³. Therefore, the number of moles of Pb⁴+ ions is:
(15 mg/cm³) x (1 g/1000 mg) x (1 cm³/1 mL) x (1500 mL) x (1 mol/207.2 g) = 0.1088 mol
Since the molar ratio between Pb⁴+ and PbBr⁴ is 1:1, the mass of PbBr⁴ needed is:
(0.1088 mol) x (287.0 g/mol) = 31.27 g