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What is the axis of symmetry for the function f(x) = 4x² - 2x - 3?

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Final answer:

The axis of symmetry for the quadratic function f(x) = 4x² - 2x - 3 is x = 1/4, calculated using the formula x = -b/(2a).

Step-by-step explanation:

The axis of symmetry for a quadratic function, such as f(x) = 4x² - 2x - 3, can be determined using the formula x = -b/(2a). This is derived from the general form of a quadratic equation, ax² + bx + c = 0. For the function in question, 'a' is 4 and 'b' is -2.

Step-by-step solution:


  1. Identify the coefficients 'a' and 'b': In our case, 'a' = 4 and 'b' = -2.

  2. Apply the formula for the axis of symmetry: x = -b/(2a)

  3. Calculate the value: x = -(-2)/(2*4) = 2/8 = 1/4.

Therefore, the axis of symmetry for the function f(x) = 4x² - 2x - 3 is x = 1/4.

User Rakesh Patanga
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