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10 votes
10 votes
The population of a pigeons in a city is

7000 and is growing exponentially at 19%
per year. Write a function to represent the
population of pigeons after t years, where
the quarterly rate of change can be found
from a constant in the function. Round all
coefficients in the function to four
decimal places. Also, determine the
percentage rate of change per quarter, to
the nearest hundredth of a percent.

User Scotty Waggoner
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1 Answer

22 votes
22 votes

Answer: p(t) = 100×1.0153^(12t)

1.53% per month

In general, the function will be written ...

p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

p(t) = 100×(1.20^(1/12))^( 12t)

p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

Explanation:

User MiraTech
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