Question

Using 2KClO3 --> 2KCl + 3O2

If you start with 1.2X10²⁴ molecules of KClO3.How many molecules of O2 will be made

Answer 1

To calculate the number of O2 molecules produced from 1.2×10²⁴ molecules of KClO3, we apply the stoichiometric ratio from the balanced equation 2KClO3 → 2KCl + 3O2, resulting in 1.8×10²⁴ molecules of O2.

Step-by-step explanation:

The question involves a stoichiometric calculation based on the chemical reaction:
2KClO3 → 2KCl + 3O2.

We are given the starting amount of KClO3 molecules, which is 1.2×10²⁴ molecules. To find the number of O2 molecules produced, we need to use stoichiometry based on the coefficients in the balanced equation.

We see that for every 2 molecules of KClO3, 3 molecules of O2 are produced. Therefore, if we start with 1.2×10²⁴ molecules of KClO3, the number of O2 molecules produced would be:

(1.2×10²⁴ molecules KClO3) × (3 molecules O2 / 2 molecules KClO3) = 1.8×10²⁴ molecules O2.