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Can someone answer this trig question?Round answers to the nearest hundredth of a foot.

a.How far is Corey from the tree in the initial position?
b.How far is Corey from the tree in the new position?
c.How many feet did Corey have to move back to get to the new position?

User Icedcoffee
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1 Answer

4 votes

Final answer:

To find the distances between Corey and the tree in different positions, we can use the Pythagorean theorem. Subtracting the distance between Corey and the tree in the new position from the initial position will give us the distance Corey had to move back.

Step-by-step explanation:

To find the answers to these questions, we need to use basic trigonometry. Let's assume that Corey is standing at point A and the tree is at point B. The distance between Corey and the tree in the initial position (question a) can be found using the Pythagorean theorem:

A^2 + B^2 = C^2

Where A represents the horizontal distance (x-coordinate), B represents the vertical distance (y-coordinate), and C represents the direct distance from Corey to the tree (hypotenuse).

In the new position, Corey has moved to point C. To find the distance between Corey and the tree in the new position (question b), we can use the same formula:

A^2 + B^2 = C^2

Finally, to find how many feet Corey had to move back to get to the new position (question c), we can subtract the distance between Corey and the tree in the new position from the distance between Corey and the tree in the initial position.

User Vinod R
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