Final answer:
The number of moles of (NH4)2SO4 in 6.60 g is approximately 0.0499 moles. There are approximately 1.534 x 10²³ molecules in 25.0 g of H2SO4. The mass of 6.25 moles of copper (II) nitrate is 1172.19 g.
Step-by-step explanation:
The total number of moles of (NH4)2SO4 in 6.60 g can be calculated by dividing the mass (6.60 g) by its molar mass. The molar mass of (NH4)2SO4 is approximately 132.14 g/mol. Thus, the number of moles = 6.60 g / 132.14 g/mol = 0.0499 moles.
For H2SO4, the number of molecules in 25.0 g can be determined by first calculating the number of moles (using the molar mass 98.08 g/mol) and then using Avogadro's number to find the number of molecules.
So, number of moles = 25.0 g / 98.08 g/mol = 0.2549 moles, and number of molecules = 0.2549 moles × 6.022 × 10²³ molecules/mol = 1.534 × 1023 molecules.
The mass of 6.25 moles of copper (II) nitrate can be calculated by multiplying the number of moles by the molar mass of Cu(NO3)2. Since the molar mass of Cu(NO3)2 is approximately 187.55 g/mol, the mass would be 6.25 moles × 187.55 g/mol = 1172.19 g.