Question

What is the energy of a photon from the violet portion of the Sun's light if it

has a frequency of 7.230 x 10¹⁴ Hz? *
A. 6.26 x 10-³⁴J/s
B. 1.09 x 10⁴⁸ J
C. 4.79 x 10-¹⁹ J
D. 9.16 c=x 10-²⁰ J"

Answer 1

To calculate the energy of a photon, we can use the equation:

E = h * f

Where:
E is the energy of the photon,
h is Planck's constant (approximately 6.626 x 10^-34 J*s),
f is the frequency of the photon.

Let's substitute the given values into the equation:

f = 7.230 x 10^14 Hz

E = (6.626 x 10^-34 J*s) * (7.230 x 10^14 Hz)

E ≈ 4.79 x 10^-19 J

Therefore, the energy of a photon from the violet portion of the Sun's light with a frequency of 7.230 x 10^14 Hz is approximately 4.79 x 10^-19 J.

The correct answer is C. 4.79 x 10^-19 J.

Answer 2

The energy of a photon with a frequency of 7.230 × 1014 Hz can be calculated using the formula E = hf, resulting in an energy of 4.79 × 10-19 J.

Step-by-step explanation:

The energy of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.626 × 10-34 J-s), and f is the frequency of the photon.

Given the frequency of the photon from the violet portion of the Sun's light as 7.230 × 1014 Hz, we can calculate the energy using:

E = (6.626 × 10-34 J-s) × (7.230 × 1014 Hz)

E = 4.79 × 10-19 J

Thus, the energy of the photon is 4.79 × 10-19 J, which corresponds to answer choice C.