Final answer:
The correct system of equations for a rectangle where the perimeter is 720 feet and the length is twice the width is l = 2w and 2l + 2w = 720. Using these equations, the dimensions are found to be l = 140 feet and w = 100 feet.
Step-by-step explanation:
The question asks for the system of equations that can be used to find the length (l) and width (w) of a rectangular lot with a given perimeter.
To solve for the dimensions of the rectangle, we use the information that the perimeter is 720 feet and that the length is twice the width.
The perimeter of a rectangle is calculated as P = 2l + 2w, where P is the perimeter, l is the length, and w is the width.
Two equations can describe this situation:
- The relationship between the length and width: l = 2w.
- The expression for the perimeter: 2l + 2w = 720.
Using these equations, we can find that the correct answer is l = 140 feet, and w = 100 feet, which means the dimensions of the lot are 140 feet by 100 feet.