Final answer:
To find the equation of a line parallel to y = 4x - 3 and passing through (-26, 20), the slope is maintained at 4 and the y-intercept is calculated, resulting in y = 4x + 124.
Step-by-step explanation:
The question involves finding the missing term in a linear equation that represents a line parallel to a given line and passing through a specific point. The original line's equation is y = 4x - 3, and the point the new line passes through is (-26, 20). Since parallel lines have the same slope, the slope of the new line will also be 4. To find the y-intercept of the new line, we use the equation y = mx + b, where m is the slope and b is the y-intercept. Substituting the given point into the equation, we have 20 = 4(-26) + b. Solving for b gives us b = 20 + 104 = 124. Thus, the equation of the parallel line is y = 4x + 124.